Question

A metal strip 6.50 cm long, 0.850 cm wide, and 0.760 mm thick moves with constant velocity through a uniform magnetic field B 1.20 mT directed perpendicular to the strip, as shown in Fig. 28-34. A potential difference of 3.90 mV is measured between points x and y across the strip. Calculate the speed v.

ence V appears across the width of ber of charge carriers per unit vol- ten with a through a uniform magnetic field

please show your work

Answer 1

( note : the speed v = 382.35 m/s is high, please check the value of potential difference is in 3.90 mV or 3.90 μV )

L= 6.50 cm = 6.50 x10 m X = d =1 = 0. So C. doy - 0.45X162 m t-0.760 mm 1 = 0.160 x103 m X x x drey X * D=90 ~B= 1.20 mł B = 1-90 x163 T + AVXY = 3.90 mv Evry = 3.907103 v (perpendicular) to the magnetic a) where the Electric field is equal field (Fe = fm? E - Bvy AVX to Alay - Bu day Avay 3.90xit 1.904483 x0.950 x 102 Bdsy [V= 389.35) mls V= 389.35

If the potential difference is 3.90 μV the answer is v = 0.382 m/s