Question

NORTH 9. (10 pts) Given Triangle below: PT Distance (ft) Azimuth 300.00 205.10 159.60 80° 290° 220° 1 N: 10000.0000 E: 10000,0000 a.Balance it by Compass Rule. (No rotation) b.Show the Final Coordinates for Point 1,2.3(4 DPA). Measured Azimuth Azimuth parture Point Distance t) Degrees Minutes seconds (degrees) Latitude ()(n 80.0000 52.0945 295.4423 300.0000 80 205.1000 290 0290.0000 70.1483 192.7310 59.6000 220 220.0000 -122.2607 -102.5889 0.0179 0.1225 SUM 664.70

Answer 1

Giundl at lat huds epaa 노 CfY) 1-2 52.09u5 95. 4423 -192.310 3-1 122.260 589 300, 0000 205 . I 000 159 60 0u 2- 2, 구어483 Eナ meede Σλ to 1-2 664 66 y.0 D55 -f어 ー(-D-0179) Lost, ラ)こ 0.0055 2o -(01225) [2 4-7') Y 3-1 59.6 --(01225)「,59.6つ) 1-0, 0295 AD 66.

Balaning ina cooidinate Nouw fina) codirek oinks Line adusted lotil adjusho |れ 1 152-09000S1 |295-4423 | 100dON | loodE 52.0gu5 %.OOS1 52 1b26 295.3869 2 0052 1026 1295 3864 2-3 | 701538 |-)927689 1122 25q10 6ise, 1 10000 OOO N叶 E+ 22.25d a 109 10오 618나, 22.256 10052. 1036 N 0 995 3889E 100此 295 386