Question

MATLAB programming

Answer 1

CODE:

A = [1 3 2; 4 17 5; 6 1 6];
%cacluclating total
B = sum(A);
%appending the total in the original 2d array
C = [A;B];
fprintf('After appedning:\n');
disp(C);

%finding max total value and its column
[m, n] = size(C);
max = -1;
maxInd = 0;
for i = 1:n
if max < C(4, i)
max = C(4, i);
maxInd = i;
end
end
fprintf('Maximum total = %d, column = %d\n', max, maxInd);

%finding min total value and its column
min = 9999999;
maxInd = 0;
for i = 1:n
if min > C(4, i)
min = C(4, i);
minInd = i;
end
end
fprintf('Minimum total = %d, column = %d\n', min, minInd);

%finding the number of elements that are greater than the average of total
avg = mean(B);
count = 0;
[m, n] = size(A);

for i = 1:m
for j = 1:n
if A(i, j) > avg
count = count + 1;
end
end
end
fprintf('Number of elements greater than the average total is: %d\n', count);

OUTPUT:

Command Window >>untitled After appedning 1 2 4 17 6 1 13 11 21 Maximum total 21, column 2 Minimum total = 1 11, column Number of elements greater than the average total is: 1

PLEASE MAKE SURE TO LIKE THE ANSWER. THANKS SO MUCH IN ADVANCE :)