Question

Need help coding this program and please explain how the operations work in pseudocode please.

Problem: Starting with the following C++ program #include <iostream> using namespace std; void main () long Var16; long Var210; long var3 = 15; long Var4 21; long Var522; long Sum; long Result; long Remainder; const unsigned byte c-6: const unsigned byte c2-10; const unsigned byte c3-15 const unsigned byte c4 21; const unsigned byte c5 22; a sm cout << "Sum is cout << "Result 13 cout << "Remainder is"<<Remainder << endl; "<<Sum << endl "<Result << endl; Inside the block denoted by the asm keyword. perform the following math 1) Add the values in variables Varl, Var2, Var3, Var4, and Var5. Place the 2) Calculate the result of the expression: (cl+c2)*(c3-c4) (c5+cl). Place the operations sum into the variable Sum result into the variable Result and the remainder of the division into the variable Remainder

Answer 1

Program

#include<iostream>
using namespace std;
int main()
{
    long Var1=6;
    long Var2=10;
    long Var3=15;
    long Var4=21;
    long Var5=22;
    long Sum;
    long Result;
    long Remainder;

    const unsigned int c1=6;
    const unsigned int c2=10;
    const unsigned int c3=15;
    const unsigned int c4=21;
    const unsigned int c5=22;

    Sum=Var1+Var2+Var3+Var4+Var5;
    Result=(c1+c2)*(c3-c4)/(c5+c1);
    Remainder=(c1+c2)*(c3-c4)%(c5+c1);

    cout<<"Sum is "<<Sum<<endl;
    cout<<"Result is "<<Result<<endl;
    cout<<"Remainder is "<<Remainder<<endl;

    return 0;
}