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THS print-out should have 27 questions. Multiple-choice questions may continue on the next column or page - find all choices
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Answer #1

Solution is attached in the image posted below.

Hope it helps.

While finding centre of gravity of only plate i took a vertices on the left bottom and add length/2 for x Axis to x ordinate of the

Vertices and add height/2 on the y ordinate of that vertices.

Addition or substraction will depend on the vertices you choose for calculating centre.

fnd Coordinate ob vextices ot First Recrangle: ES-616 A CR-6) S6) calculating Length & oiah Ob NOn f Lat plate S,6) 6 C-s,-6

Lience Cenue ob Plate mlu L1,0 HOring Cculau paut is CIeau thai Centue ob Cucie Coinciae oith Centue ob plate Hence Cenue Ob

AiF ABXCD 12X12 Iu umi4 A2= Io2: 20.23 uni ロx 62 AS auea Ob Ciuculau paut is mot theie hence it Nill be Aubstracteo A212 AXI

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