Question

What is the shortest wavelength of the continuum produced by an X-ray tube having a silver target and operated at 97 kV?

Answer 1

we have than the energy for a wavelength is $E = \frac{hc}{\lambda }$ h = planck ctte = 4.18x10^-18KeV/s c= 2.9979x10⁸m/s and the we have E = 1.2397x10^-9/$\lambda$ =) $\lambda$  =1.2397x10^-9/E =)$\lambda$  = 1.2397x10^-9Kev m/97Kev =) $\lambda$  = 1.27x10^-11m

$\lambda$  = 1.27x10^-11m