1) a) pH = -log[H3O+]= 3.21
Thus, [H3O+] = 10-3.21 = 6.2 x 10-4 M
b) pOH = 13.34
we know that, pH +pOH = 14
Thus, pH= 14 - 13.34 = 0.66
-log[H3O+]= 0.66
Thus, [H3O+] = 10-0.66 = 0.22 M
Calculate the [H_3O^+] for the following conditions a. pH = 3.21 b. pOH= 13.34 Calculate the...
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