H2o+cl2o.....>2hocl Starting conc for h20 and cl2o is 0.0032 M and the equilibrium concentration for hocl...

Question

Question

H2o+cl2o.....>2hocl

Starting conc for h20 and cl2o is 0.0032 M and the equilibrium concentration for hocl is 0.0012M. What is value of equilibrium constant.

science chemistry

Answer 1

Answer #1

Answer 2

Similar Homework Help Questions

Consider the following reaction and the value of its equilibrium constant: H2O(g) + Cl2O(g) ⇌ 2HOCl(g)...

Consider the following reaction and the value of its equilibrium constant: H2O(g) + Cl2O(g) ⇌ 2HOCl(g) Keq = 0.090 If the equilibrium concentration of HOCl is measured at 0.15 M, what are the equilibrium concentrations of H2O and Cl2O, assuming that they are equal?
At 25oc, Kc = 0.090 for the following reaction. H2O(g) + Cl2O(g) 2 HOCl(g) Calculate the...

At 25oc, Kc = 0.090 for the following reaction. H2O(g) + Cl2O(g) 2 HOCl(g) Calculate the equilibrium concentration of all species if the initial concentration of HOCl = 1.50 M. H2O(g) + Cl2O(g) 2 HOCl(g) Start Change Equil.
1. At 25oc, Kc = 0.090 for the following reaction. H2O(g) + Cl2O(g) 2 HOCl(g) Calculate...

1. At 25oc, Kc = 0.090 for the following reaction. H2O(g) + Cl2O(g) 2 HOCl(g) Calculate the equilibrium concentration of all species if the initial concentration of HOCl = 1.50 M. H2O(g) + Cl2O(g) 2 HOCl(g) Start Change Equil.

For the following process: H2O(g) + Cl2O(g) à 2HOCl(g) Ho(H2O(g))= 242KJ/mol Ho(Cl2O(g))=80KJ/mol Ho(HOCl(g))= -80KJ/mol So(H2O(g))= 0.189...

For the following process: H2O(g) + Cl2O(g) à 2HOCl(g) Ho(H2O(g))= 242KJ/mol Ho(Cl2O(g))=80KJ/mol Ho(HOCl(g))= -80KJ/mol So(H2O(g))= 0.189 KJ/K So(Cl2O(g))=0.266 KJ/K So(HOCl(g))= 0.237 KJ/K A) Calculate ΔHo, ΔSo and ΔGo B)Calculate ΔG at 100K and P(H2O)=P(Cl2O)= P(HOCL)=10atm
At 25°C, K = 0.090 for the following reaction. H2O(g) + Cl2O(g) ⇌ 2 HOCl(g) Calculate...

At 25°C, K = 0.090 for the following reaction. H2O(g) + Cl2O(g) ⇌ 2 HOCl(g) Calculate the concentrations of all species at equilibrium for each of the following cases. (a) 1.0 g H2O and 2.0 g Cl2O are mixed in a 1.1 L flask. [HOCl]_______ M [Cl2O]_______ M [H2O]_______ M (b) 1.2 mol pure HOCl is placed in a 2.2 L flask [HOCl]______ M [Cl2O]______ M [H2O]______ M
13. The reaction H2O (g) + Cl2O (g) ⇄ 2 HOCl (g) has Kc = 0.0900...

13. The reaction H2O (g) + Cl2O (g) ⇄ 2 HOCl (g) has Kc = 0.0900 at 25°C. A reaction mixture initially contains 0.00432 M H2O and 0.00432 M Cl2O. Calculate the equilibrium concentrations of all reactants and products.

A mixture of 0.505 M H2O , 0.378 M Cl2O , and 0.747 M HClO are...

A mixture of 0.505 M H2O , 0.378 M Cl2O , and 0.747 M HClO are enclosed in a vessel at 25°C . H2O(g)+Cl2O(g)−⇀↽−2HOCl(g)Kc=0.0900 at 25°C Calculate the equilibrium concentrations of each gas at 25°C . A mixture of 0.505 M H,0,0.378 M C1,0, and 0.747 M HCIO are enclosed in a vessel at 25°C. H2O(g) + C1,0(g) = 2 HOCI(g) Kc = 0.0900 at 25°C Calculate the equilibrium concentrations of each gas at 25 °C.
For the reaction H2O(g)+Cl2O(g)<->2HOCl, K=0.900 at 25 degrees Celsius. What are the equilibrium concentrations of each...

For the reaction H2O(g)+Cl2O(g)<->2HOCl, K=0.900 at 25 degrees Celsius. What are the equilibrium concentrations of each species beginning with 0.300 M of each reactant? Complete the ICE table Solve for the equilibrium concentrations asked for Briefly describe what simplification would be needed to complete the question
A mixture of 0.482 M H20, 0.419 M Cl20, and 0.748 M HCIO are enclosed in...

A mixture of 0.482 M H20, 0.419 M Cl20, and 0.748 M HCIO are enclosed in a vessel at 25 °C. (Reaction) H2O(g) + C12O (g) <------> 2HOCI(g) Kc = 0.090 at 25 °C Calculate the equilibrium concentrations of each gas at 25 °C [H2O] = M [Cl2O] = M [HOCL]= M

In the following reaction, the initial concentrations of the reacting mixture contains the [H2O] = 1.00...

In the following reaction, the initial concentrations of the reacting mixture contains the [H2O] = 1.00 M and [Cl2O] = 1.00 M at 25 deg C. The mixture is allowed to come to equilibrium. H2O(g) + Cl2O(g) <=> 2HOCl(g) ; Kc = 0.0900 Determine the Kp value of the reaction.