Question

What volume of a 0.500 M HCl solution is needed to completely neutralize 10.0 mL of a 0.200 M Ba(OH)2 solution? Ba(OH)2(aq) + 2 HCl(aq) → BaCl2(aq) + 2 H2O(l) a. 10.0 mL b. 4.00 mL c. 2.00 mL d. 8.00 mL

Answer 1

2HCl(aq)-Ba(OH),(aq) →BaCL(aq)-H,O(1) Concentration of Ba(OH)0.200 Volume ofBa (OH), =10.0 mL mol 1000mL 00100 L mol Number of moles ofBa (OH),-00100 L × 0.200 -2.00 x103 mol 2molHC molBa(OH). Number of moles of HCl i s needed 2.00 x 10-3 mol B a ( OH ), x -4.00x10-3 mol HC1 mol Concentration of HC1-0.500- Volume ofHC1-4.00 x 10-3 molx- 0.500mol 1000 mL 0.008 × =8.00 mL Hence, 8.00mL | of HCl is needed.