Question

11.9 Week 11 Lab: 2D Arrays For this lab, you only need to write a single user-defined function that analyzes a 2D array of chars. You do NOT need to write any of the code in main0 that calls your function. Make sure to use the template and only add code to the user-defined function. Write a function win0 with the following definition (i.e. prototype): int win(char board17)15), char player) The function win0 should return a 1 if the character player is found in three consecutive positions in the board. Consecutive for this lab means in the same row or in the same column, NOT on a diagonal. For the board shown below B B D E A B G G Z B A G G око B B D E

Answer 1

C code

#include<stdio.h>
#include<stdlib.h>

int win(char board[7][5], char player){

//looping variables
int i,j;
//checking consecutive positions in a row

//for looping through the rows
for(i=0;i<7;i++){
//for looping through the columns
//in this loop 3 elements are bring compared at once
//so the loop starts from 1 and ends at 3
//because j-1,j and jth elements are being considered
for(j=1;j<4;j++){
//if the given character is present in these 3 consecutive positions
//then 1 will be returned by the function
//in the if condition the row variable 'i' is same
//and the column variable 'j' is changed for checking the values in a single row
if( (board[i][j-1]==player) && (board[i][j]==player) && (board[i][j+1]==player)){
return 1;
}
}
}

//now we check for consecutive positions in a column

//for looping through the column
for(i=0;i<5;i++){
//for looping through the columns
//as 3 elements are being checked at once
//so the loop will run from 1 to 5
for(j=1;j<6;j++){
//here the column variable 'i' is kept constant
//and the row variable 'j' is changed for checking values
//in a single column
//if three consecutive values are found then 1 is returned
if( (board[j-1][i]==player) && (board[j][i]==player) && (board[j+1][i]==player)){
return 1;
}
}
}
//if no value is returned from the execution of above loops
//then the given character is not present consecutively
//so 0 will be returned
return 0;
}

int main() {
//initialize the array
char board[7][5];
int i,j;
char user;
int gameresult;

//read the board
printf("Enter 35 values for the 7X5 game board\n");
for(i=0;i<7;i++){
for(j=0;j<5;j++){
scanf(" %c",&(board[i][j]));
}
}

//print the board
for(i=0;i<7;i++){
for(j=0;j<5;j++){
printf(" %c",(board[i][j]));
}
printf("\n");
}

printf("Enter the user's token to see if they won the game!");
scanf(" %c",&user);
printf("\n\n");

gameresult = win(board,user);

if(gameresult==1)
printf("Player %c won the game!",user);
else if(gameresult==0)
printf("Player %c didn't win.",user);
else
printf("Invalid response from win()\n");

return 0;

}

***Important Note***

One very important that needs to be taken care of here is how you take character input.

The %c conversion specifier won't automatically skip any leading white space, so if there's a stray newline in the input stream (from a previous entry, for example) the scanf call will consume it immediately.

This problem can be solved by putting a white space before the conversion specifier in format string.

scanf(" %c", &c);

The blank in the format string tells scanf to skip leading whitespace, and the first non-whitespace character will be read with the %c conversion specifier.

SnapShots of the code

# include<stdio.h> # include<stdlib . h> int win (char board[7] [5], char player) t hooping variables int i,j //checking consecutive //for looping through the for (i#0 ; i< 7 ; i++) { positions in a row rows //for looping through the columns //in this loop 3 elements are bring compared at once //so the loop starts from 1 and ends at 3 //because -1, and ih elements are being considered for (j=1;jd;j++) { //if the given character is present in these 3 consecutive positions //then 1 will be returned by the function //in the if condition the row variable i is same //and the column variable is changed for checking the values in a single row if( (board[i] j-1]--player)&&(board[il j1--player) && (board[i] 3+1-player)) return l:

//now we check for consecutive positions in a colum //for looping through the colum for (i=0;i< 5 ; i++) { //for looping through the columns //as 3 elements are being checked at once //so the loop will run from 1 to 5 for (j=1 6:3++) { /Phere the column variable is kept constant //and the row variable is changed for checking values //in a single column //if three consecutive values are found then 1 is returne if (boardj-1] [i]--player)&& (board[j] [i]-player) &&(boardlj+1]i]--player)) return 1; /lif no value is returned from the execution of above loops //then the given character is not present consecutively //so 0 will be returned return 0:

int main) initialize the array char boardt7] 151: int i,j: char user; int gameresult; //read the board printf ("Enter 35 values for the 7X5 game board\n") for (i-0:i<7:i++) for (1-0:3<5:j+) scanf ( " %c", & (board [1] [j] ) ) ; //print the board for (i=0;i<7:1++) { for (1-0:3<5:j+) printf (" %c", (board [1] [j] ) ) ; printf ("n") printf ("Enter the user's token to see if they won the game!") scanf ( " %c", &user) ; printf("Inin") gameresult win (board, user)

if (gane result=1) printf ("Player %c won the game!", user); printf( "Player %c didn't win.", user); printf ("Invalid response from win)In") else ifgame result 0) else return 0

Output

Enter 35 values for the 7X5 game board A B B DE ZABGG ZBAGG ZZX GK A B B DE A B B DE Z A BGG Z BAGG A B B DE Enter the user's token to see if they won the game!G Player G won the game! process returned θ (0x0) execution time : 76.119 s Press any key to continue.

Enter 35 values for the 7X5 game board A B B DE ZABGG ZBAGG ZZX GK A B B DE A B B DE Z A BGG Z BAGG A B B DE Enter the user's token to see if they won the game!A Player A didn't win. process returned θ (0x0) execution time : 6.910 s Press any key to continue.