Question

Matlab

A really nice Math Professor gives out large sums of cash for correct answers in class. Each student gets $1000 for each of their first three correct answers (paid by the Professor to the student), each student then gets $500 for each of their next 24 correct answers, while for every subsequent correct answer they make, the student has to pay the Professor $5, as a fine for talking too much. (Note: this is a fake scenario, set in a world of high fantasy, with hobbits and elves. It’s not real life. I don’t have pointy ears.)

(First 3 correct answers get $1000 EACH.
The next 24 correct answers get $500 EACH.
The next correct answer (i.e., your 28th correct answer) costs you $5 (but you get to keep all the money you earned from your previous 27 correct answers). All your next correct answers (i.e., your 29th, 30th, etc) all cost you $5 each.)

(a) Write a Matlab function file that inputs the number of correct answers, and outputs the amount of money the student receives (or pays).

(b) How many correct answers from any individual student does it take before the Math Professor starts to make a profit from that student?

Answer 1

Solution: function f = Correct (n) % Initialize variables total-n; % First three questions if n>=3 pay 3*1000; n-n-3 end Next 24 questions if n-24>0 500 pay pay+24 n=n-24; else pay-paytn*500: n-n-24 end Remaining questions if n>0 Remaining questions upto start of proiit while pay>0 if n= 0 break; end

pay-pay-5; n-n-l; end end Remaining questions if n>0 disp ("Number of correct answer before Maths professor start to take profit") disp (total-n) pay-pay-(n*5); disp 'Amount of money student disp (pay) disp 'Amount of money student has to disp (abs (pay)) end if pay>0 recieve') else end end Output:

>x-3030 3030 >>Correct (x) Before profit number of correct answer is 3027 Amount of money student has to pay 15

Code:

function f = Correct(n)

% Initialize variables

pay=0;

total=n;

% First three questions

if n>=3

pay=3*1000;

n=n-3;

end

% Next 24 questions

if n-24>0

pay=pay+24*500;

n=n-24;

else

pay=pay+n*500;

n=n-24;

end

%Remaining questions

%Remaining questions upto start of profit

    if n>0

        while pay>0

            if n==0

                break;

            end

            pay=pay-5;

            n=n-1;

        end

      

    end

    % Remaining questions

    if n>0

disp("Number of correct answer before Maths professor start to take profit")

          disp(total-n)

        pay=pay-(n*5);

    end

    if pay>0

        disp('Amount of money student recieve')

        disp(pay)

    else

        disp('Amount of money student has to pay')

        disp(abs(pay))

    end

end