Answer: Pbar= total dissatisfied patients/total observations= 95/480= 0.198~0.20
UCLp= 0.416~0.42, LCLp= 0.00
Explanation:
| Sample | defectives | observation |
| 1 | 4 | 30 |
| 2 | 2 | 30 |
| 3 | 8 | 30 |
| 4 | 9 | 30 |
| 5 | 5 | 30 |
| 6 | 10 | 30 |
| 7 | 8 | 30 |
| 8 | 9 | 30 |
| 9 | 7 | 30 |
| 10 | 4 | 30 |
| 11 | 3 | 30 |
| 12 | 2 | 30 |
| 13 | 1 | 30 |
| 14 | 6 | 30 |
| 15 | 12 | 30 |
| 16 | 5 | 30 |
| total | 95 | 480 |
| steps and formulas, 3 sigma process | ||
| P= | total defective/total observations | 0.198 |
| Q= | 1-P | 0.802 |
| N= | average sample size | 30 |
| Standard deviation | squareroot(P*Q/N) | 0.073 |
| UCL= | P + 3*squareroot(P*Q/N) | 0.416 |
| LCL= | P - 3*squareroot(P*Q/N) | -0.020 |
| defects cannot be negative, therefore negative LCL is taken as '0' | 0.000 | |
Answer b: Yes the process is in control, No data point is beyond control limits.

| Sample | defectives | observation | proportion= defectives/observations | UCL | LCL | P |
| 1 | 4 | 30 | 0.133 | 0.416 | 0.000 | 0.198 |
| 2 | 2 | 30 | 0.067 | 0.416 | 0.000 | 0.198 |
| 3 | 8 | 30 | 0.267 | 0.416 | 0.000 | 0.198 |
| 4 | 9 | 30 | 0.300 | 0.416 | 0.000 | 0.198 |
| 5 | 5 | 30 | 0.167 | 0.416 | 0.000 | 0.198 |
| 6 | 10 | 30 | 0.333 | 0.416 | 0.000 | 0.198 |
| 7 | 8 | 30 | 0.267 | 0.416 | 0.000 | 0.198 |
| 8 | 9 | 30 | 0.300 | 0.416 | 0.000 | 0.198 |
| 9 | 7 | 30 | 0.233 | 0.416 | 0.000 | 0.198 |
| 10 | 4 | 30 | 0.133 | 0.416 | 0.000 | 0.198 |
| 11 | 3 | 30 | 0.100 | 0.416 | 0.000 | 0.198 |
| 12 | 2 | 30 | 0.067 | 0.416 | 0.000 | 0.198 |
| 13 | 1 | 30 | 0.033 | 0.416 | 0.000 | 0.198 |
| 14 | 6 | 30 | 0.200 | 0.416 | 0.000 | 0.198 |
| 15 | 12 | 30 | 0.400 | 0.416 | 0.000 | 0.198 |
| 16 | 5 | 30 | 0.167 | 0.416 | 0.000 | 0.198 |
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