Question

please solve 4th and 5th question. 5th question is depending on 4 question. Thank you :)

Answer 1

Note: - In calculation dB is converted to values 0 dB rightarrow 10 degree = 1, - 10 dB rightarrow 10^- 1 = 0.1 20 dB rightarrow 10^- 2 = 0.9 Mean excess delay (z) z = (0) (1) + (50) (1) + (75) (0.1) + (100) (0.01)/(1) + (1) + (0.1) + (0.01) = 27.725 ns second moment: z^2 = (0) (1)^2 + (1) (50)^2 + (0.1) (75)^2 + (0.01) (100)^2/1 + 1 + 0.1 + 0.01 = 1498.815 ns^2 \r\n RMS delay spread delta_ v = squareroot z^2 - (z)^2 = 27,02 mu s coherence bandwidth Rightarrow B_ c = 1/5 delta_ v = 7.401 k Hz A signal with 300 k Hz bandwidth when pass through will experience frequency selective finding as B(300 k Hz) > B_ c