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(6 points) A poll conducted in 2013 found that the proportion of of U.S. adult Twitter users who get at least some news on Twitter was 0.52. The standard error for this estimate was 0.024, and a normal distribution may be used to model the sample proportion. 1. Construct a 99% confidence interval for the proportion of U.S. adult Twitter users who got some news on Twitter. Round to three decimal places. to 2. Identify each of the following statements as true or false. ? ? ? 1. Based on the interval, it is reasonable to believe that at least half of U.S. adult Twitter users get some news through Twitter. 2. Since the standard error is 2.4%, we can conclude that 97.6% of all U.S. adult Twitter users were included in the study. 3. If we construct a 90% confidence interval for the percentage of U.S. adults Twitter users who get some news through Twitter, this ▼ confidence interval will be narrower than a corresponding 99% confidence interval. ? A 4. If we want to reduce the standard error of the estimate, we should collect less data.1,2,3,4 is True/False

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52%, adult tu, ite,roses get at least some news Standarel e o this estimate 024 tusitf er. Co tiden The q9% confiden co intervaL İS ラ> Pt 7, ,(S . E ) = 0.52±(2.576乂0,024 = 0.52-0.0618-0.4582 = 0.52十0.06/6= 0.5818 Co, 4582, ‘,5818 ) I FALSE, as less than o.5 is less than i stan dardee omo.52 , Sothat is in sigmificant. 2. FALSE , standard rro is not stelatee ith the 추 FALSE, us e S hos!d allect met, data, as tho Standard error is inverse!オ Pro P tional to tho 3. FALSEaaer co nficlen c levet has ses a ose oidth ,shen euerything etse t the sam e

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