Solution :
Given that 118,228,309,289,413,518,331,46,389,72,89,133,357,415,385,42,476,170,40,103,121,75,315,334,402,138,324,289,331
class Frequency midpoint Relative cumulative
Frequency Frequency
40 - 129 9 84.5 9/29 = 0.310 9
130 - 219 3 174.5 3/29 = 0.103 9 + 3 = 12
220 - 309 4 264.5 4/29 = 0.138 12 + 4 = 16
310 - 399 8 354.5 8/29 = 0.276 16 + 8 = 24
400 - 489 4 444.5 4/29 = 0.138 24 + 4 = 28
490 - 579 1 534.5 1/29 = 0.034 28 + 1 = 29
=> Total frequency = 29
=> Relative frequency = frequency/Total frequency
=> A cumulative frequency distribution is the sum of the class and all classes below it in a frequency distribution
==> The class with the greatest frequency is from 40 to 129
==> The class with the least frequency is from 490 to 579
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