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- Strategies for treating hypertensive patients by nonpharmacologic methods are compared by establishing three groups of hype

#2: Using the data from Problem #1 above, we want to use the Bonferonni method to test the following hyptheses at the 6% sign

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Answer #1
treatment I II III
count, ni = 3 3 4
mean , x̅ i = 4.100 3.23 0.825
std. dev., si = 0.656 1.137 1.170
sample variances, si^2 = 0.430 1.293 1.369
total sum 12.3 9.7 3.3 25.3 (grand sum)
grand mean , x̅̅ = Σni*x̅i/Σni =   2.53
square of deviation of sample mean from grand mean,( x̅ - x̅̅)² 2.465 0.495 2.907
TOTAL
SS(between)= SSB = Σn( x̅ - x̅̅)² = 7.395 1.484 11.628 20.50683
SS(within ) = SSW = Σ(n-1)s² = 0.860 2.587 4.108 7.554

no. of treatment , k =   3
df between = k-1 =    2
N = Σn =   10
df within = N-k =   7
  
mean square between groups , MSB = SSB/k-1 =    10.2534
  
mean square within groups , MSW = SSW/N-k =    1.0792
  
F-stat = MSB/MSW =    9.5012

anova table
SS df MS F p-value
Between: 20.507 2 10.2534 9.501 0.0101
Within: 7.554 7 1.0792
Total: 28.061 9

================

The Bonferroni correction sets the significance cut-off at α/n = 0.06/3 = 0.02

MSE=   1.079

test statistic = ( x̅ i -x̅ j) /√(MSE(1/ni+1/nj))

answer: 1.02 , 4.13 , 3.04

b)

α=0.02

no. of treatments,k=   3
DF error =N-k=   7
t-critical value,t(α/2,df)=   2.9980

if test stat > critical value, means are significantly different

t-critical value test statistic result
µ1-µ2 2.998 1.02 means are not different
µ1-µ3 2.998 4.13 means are different
µ2-µ3 2.998 3.04 means are different

answer: option H)

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