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Bob and Doug are playing the following game. Bob starts by rolling two fair dice; if...

Bob and Doug are playing the following game. Bob starts by rolling two fair dice; if the sum of his dice is six, then he wins the game. If not, then Doug rolls the dice, and if the sum of his rolls is seven, then he wins the game. If neither player wins the game during the first round, then they repeat the process (with Bob going first) until someone wins a round. What is the probability that Bob wins this game? Is he more or less likely than Doug to win?

math   Statistics-And-Probability   
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Answer #1

two B Dough X= av of having a Y = or of having a n Sum = 6 upon sum= 7 upon rolling solling two fair dice 1 fais dice Die-1-

P (Probability that bob wins ) = is given below

7 Bob wing in it sound +(Bob lose) (Bob wins zud cound tl Bod lose \ аnd ( S (se (2nd round /s, 30 & trouund te - Soon. 1. =)

& p ( Bob wine soe ) = 36 l ( Bob mines , a tatat I the game / sum of top of seine 3 cephe Pause cocesi Sao C T- 18 term olen

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