Question

The glass tube inside the photocell that contains the anode and the cathode must be evacuated of all air molecules. This is done in order to prevent any potential collisions between the ejected electrons and the air molecules. What would be the result of such a collision occurring? Select one: a. The ejected electron will lose some of its kinetic energy due to a collision with an air molecule which would cause the stopping potential recorded to be higher. b. The ejected electron will lose some of its kinetic energy due to a collision with an air molecule, but that will not interfere with the results of the experiment in any way. c. The ejected electron will gain more kinetic energy due to a collision with an air molecule which would cause the stopping potential recorded to be lower. d. The ejected electron will lose some of its kinetic energy due to a collision with an air molecule which would cause the stopping potential recorded to be lower.

Stopping potential as in (Vs)

Answer 1

Correet anewertld) The ejected elecon will lose some kolE due to collision, which would cause the Stopping potential to be lower. because of collision K. E is decreased, so now it will take less energy to stop the electron or we can say Stopping potential will be less as compared to the Case without collision.