Question 8-24 from Statics by Hibbeler 14th ed

if the system is in equilibrium, the net torque is zero.
0 = 30(5) - N(24)
N = 6.25 lb
If the system is in equilibrium, the net force exerted on
system along the x-axis is zero.
0 = 6.25 - FA
FA = 6.25 lb
If the system is in equilibrium, the net force exerted on
system along the y-axis is zero.
0 = NA - 30
NA = 30 lb
Hence, the maximum force FA,max is,
FA,max = usNA = (0.3)(30 lb) = 9 lb
This value is greater than 6.25 lb.
Yes, the pole is at stationary.
Question 8-24 from Statics by Hibbeler 14th ed *8-24. The uniform thin pole has length of...
The uniform pole of length L is supported on the wall
as indicated. If the coefficient of static friction between the
bearing surfaces and the ends of the post is 0.25, calculate the
maximum angle under which the post can be placed without starting
to slip.
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solve some parts of question
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summatize the following info and break them into differeng key points. write them in yojr own words
apartus
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