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Diagonalize the following matrix. The real eigenvalues are given to the right of the matrix. 1 -4 4 12 - 15 12 ; 2 = -3,5 16

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let A= 1 12 16 - 4 - 15 -16 4 ] 12 13 J. (A +31) - 1 4 -4 47 -12 12 0 0 -16 16.1.100 det (A + 3) = 0 & lim (Null (A +3I)) = 2is the eigenvector of 7225. p ! 1 To - 0 1 3 4 D2 -3 0 0 0 0 2 - 3 0 0 5 So, Ais diagonalizable. & B is right

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