Question

64) At elevated temperatures, methylisonitrile (CH3NC) isomerizes to acetonitrile (CH3CN): CH3NC (g) CH33CN (g) The reaction is first order in methylisonitrile. The attached graph shows data for the reaction obtained at 198.9°C. In pressure, CHANC 30,000 s-1 10,000 20,000 Time (s) The rate constant for the reaction is A)-1.9 ~ 104 B) +1.9 ~ 104 C) -5.2 x 10-5 D) +5.2 x 10-5 E) +6.2 Answer: B

the answer should be B apparently. Solve this by using the first order formula and don't use the slope of the line formula. I know it's the same but I would prefer to see it by the first order formula

Answer 1

The first onder rate equation in terms of Pressure is given below Pf - Pt K = Rate Constant Pr - Pressure at end of reachion Po - Initica poressure , P = Paressure at time 't'. - Po= Initial pe At 5.0 5.0 2.303 2.1971 7 - logp. - 5. a = 2.171 - Taking Antilog both sides we get P. = 10^2-1), 148.25 atm At t = 5000 gec lipt = 4.8 P. 4.2 = 2.084 Pt = 102.004 , 131.33 atm At the end of the reaction en pf = 3.4 = 3.4 2.303 Pf = 10^1.4763 = 29.94 atm loght = 2.303 1.4763 + - aged long lost the 148.25 K = 2.303 log 74 29.94 - 5, 000%e0 29.94 - 121-33) 2.303 5,ODD sex ero 0.1119 ) Ang was TK = +5.2 x 10 sec option (D) is correct 1