Question

(10%) Problem 4: A wad of clay m/=0.33 kg is thrown in the x direction with an initial velocity of v = 29 m/s. It collides with a cube of m2 = 3.9 kg initially at rest and sticks. - 33% Part (a) Write an expression for the system's final velocity v A 33% Part (b) Assume the cube had an initial velocity of v) in the positive x direction. Write an expression for the final velocity of the system. A 33% Part (e) If the cube has an initial velocity of v = 2.3 m/s, what is the final velocity of the system in meters per second? Grade Summary Deductions 09

Answer 1

part A)

for the final velocity, vf

Using conservation of momentum

m1 * v = (m1 + m2) * vf

vf =(m₁ * v )/(m₁ + m₂)

part B)

if the cube has initial velocity

Using conservation of momentum

m1 * v + m2 * vb = (m1 + m2) * vf

vf = (m₁ * v + m₂ * v_b)/(m₁ + m₂)

part c)

putting the values

vf = (0.33 * 29 + 2.3 * 3.9)/(0.33 + 3.9)

vf = 4.38 m/s

the final velocity is 4.38 m/s