A mixture of gold, zinc and mercury contains 105 g of gold, 0.662 lb of zinc...
A mixture of gold, zinc and mercury contains 105 g of gold, 0.662 lb of zinc and 85.0 mL of mercury (Density= 13.6 g/mL). What is the % compostion of each of the three metals in the mixture?
Homework Answers
First, use mass composition, so change volume to mass
D = mass/Vol
mass = D*V = 85*13.6 = 1156 g of Mercury
mass of gold = 105 g
mass of zinc = 0.662 lb --> 0.662 *454 = 300.548 g of zinc
Total mass = 300.548+105+1156 = 1561.548 g
% Gold = 105/1561.548*100 = 6.724%
% Zinc = 300.548/1561.548*100 = 19.24%
% Merucury = 1156 /1561.548*100 = 74.02 %
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