a)as 5 ,6 are two outcomes out of 6 , therefore P(a single die shows 5 or 6) =2/6
P(all three are either 5 or 6) =(2/6)*(2/6)*(2/6)=1/27
b P(all three are even) =(1/2)*(1/2)*(1/2)=1/8
c) P(no rolls are 5) =(5/6)*(5/6)*(5/6) =125/216
d) P(At least one is 5) =1-P(none is 5) =1-125/216 =91/216
e) Probability= (!/6)*(1/6)*(3/6) =1/72
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