A 5.4 kg cat and a 2.3 kg bowl of tuna fish are at opposite ends of the 4.0-m-long seesaw. (Figure 1)
Part A: How far to the left of the pivot must a 3.8 kg cat stand
to keep the seesaw balanced? 
Homework Answers
1. A 5.4 kg cat and a 2.1 kg bowl of tuna fish are at opposite...
1. A 5.4 kg cat and a 2.1 kg bowl of tuna fish are at opposite ends of the 4.0-m-long seesaw. (Figure 1) How far to the left of the pivot must a 3.7 kg cat stand to keep the seesaw balanced? Express your answer to two significant figures and include the appropriate units. 2. Vector A⃗ =5i^+3j^ and vector B⃗ =3i^−6j^+4k^. Part A:What is the cross product A⃗ ×B⃗ ? Find the x-component. Part B: Find the y-component. Part...
A 5.0 kg cat and a 2.5 kg bowl of tuna fish are at opposite ends of a 4.0-m-long...continues
A 5.0 kg cat and a 2.5 kg bowl of tuna fish are at opposite ends of a 4.0-m-long seesaw. How far to the left of the pivot must a 3.9 kg cat stand to keep the seesawbalanced?
Two children are sitting on opposite ends of a scesaw of negligible mass. If 40 kg...
Two children are sitting on opposite ends of a scesaw of negligible mass. If 40 kg child is 2.0 m from the pivoted point, how far from the pivot point will the other 30 kg child sit on the seesaw to be at equilibrium? (draw diagram to show vectors) A uniform 2000 kg beam 10 m long supports a 500 kg weight 3 meters from the right support. Calculate the forces on each of the vertical support columns? (draw diagram...
Jason, 650 N, and Jane, 450 N, stand on opposite ends of a balanced seesaw. How...
Jason, 650 N, and Jane, 450 N, stand on opposite ends of a balanced seesaw. How far (x) is Jason from the fulcrum when Jane is 3.0 m from the fulcrum?
dont know what im doing wrong Suppose a 28.4-kg child sits 0.67 m to the left...
dont know what im doing wrong
Suppose a 28.4-kg child sits 0.67 m to the left of center on the same seesaw as the problem you just solved in the PRACTICE IT section. A second child sits at the end on the opposite side, and the system is balanced. (a) Find the mass of the second child. 8.55 kg (b) Find the normal force acting at the pivot point. 362 Your answers to part (a) and (b) are not consistent....
Need help with part C. Thank you! This is the figure above. However, it has different...
Need help with part C. Thank you!
This is the figure above. However, it has different values than
the homework question above.
PRACTICE IT Use the worked example above to help you solve this problem. A woman of mass m = 53.6 kg sits on the left end of a seesaw-a plank of length L = 4.39 m, pivoted in the middle as shown in the figure. (a) First compute the torques on the seesaw about an axis that passes...
Question 2 (2 Points) Static Equilibrium - Modified Seesaw (including mass of the seesaw) The two...
Question 2 (2 Points) Static Equilibrium - Modified Seesaw (including mass of the seesaw) The two children shown in the Figure are balanced on a seesaw. The first child has a mass of m1= 16.2 kg and sits r1 = 2.1 m from the pivot. The center of mass of the seesaw is r3 = 0.36 m to the left of the pivot (on the side of the lighter child) and assume a mass of M = 13.4 kg for...
I need help with exercise and practice it. PRACTICE IT Use the worked example above to...
I need help with exercise and practice it.
PRACTICE IT Use the worked example above to help you solve this problem. m 56.3 kg sits on the left end of a seesaw A woman of mass -a plank of length L 4.68 m, pivoted in the middle as shown in the figure (a) First compute the torques on the seesaw about an axis that passes through the pivot point. Where should a man of mass M = 74.9 kg sit...
Two identical 0.800-kg masses are pressed against opposite ends of a light spring of force constant...
1. Two identical 0.800-kg masses are pressed against opposite ends of a light spring of force constant 1.75 N/cm, compressing the spring by 11.0 cm from its normal length.Part AFind the speed of each mass when it has moved free of the spring on a frictionless, horizontal table.Express your answer with the appropriate units.2. A 15.0 kg fish swimming at 1.40 m/s suddenly gobbles up a 4.50 kg fish that is initially stationary. Neglect any drag effects of the water.Part...
torque rotational equilibrium 2. A 10 kg cat walks along a 3 m long plank with...
torque rotational equilibrium
2. A 10 kg cat walks along a 3 m long plank with a mass of 4 kg that is supported by two sawhorses. The right sawhorse is 0.7 m from the end of the plank. How far from the end of the right sawhorse can she walk before tipping the plank over. 3. Nintendo has designed a new minigame for the next Sonic Party. In the game, players have to balance a rigid body. Where should...
Two children are sitting on opposite ends of a scesaw of negligible mass. If 40 kg child is 2.0 m from the pivoted point, how far from the pivot point will the other 30 kg child sit on the seesaw to be at equilibrium? (draw diagram to show vectors) A uniform 2000 kg beam 10 m long supports a 500 kg weight 3 meters from the right support. Calculate the forces on each of the vertical support columns? (draw diagram...
dont know what im doing wrong
Suppose a 28.4-kg child sits 0.67 m to the left of center on the same seesaw as the problem you just solved in the PRACTICE IT section. A second child sits at the end on the opposite side, and the system is balanced. (a) Find the mass of the second child. 8.55 kg (b) Find the normal force acting at the pivot point. 362 Your answers to part (a) and (b) are not consistent....
Need help with part C. Thank you!
This is the figure above. However, it has different values than
the homework question above.
PRACTICE IT Use the worked example above to help you solve this problem. A woman of mass m = 53.6 kg sits on the left end of a seesaw-a plank of length L = 4.39 m, pivoted in the middle as shown in the figure. (a) First compute the torques on the seesaw about an axis that passes...
Question 2 (2 Points) Static Equilibrium - Modified Seesaw (including mass of the seesaw) The two children shown in the Figure are balanced on a seesaw. The first child has a mass of m1= 16.2 kg and sits r1 = 2.1 m from the pivot. The center of mass of the seesaw is r3 = 0.36 m to the left of the pivot (on the side of the lighter child) and assume a mass of M = 13.4 kg for...
I need help with exercise and practice it.
PRACTICE IT Use the worked example above to help you solve this problem. m 56.3 kg sits on the left end of a seesaw A woman of mass -a plank of length L 4.68 m, pivoted in the middle as shown in the figure (a) First compute the torques on the seesaw about an axis that passes through the pivot point. Where should a man of mass M = 74.9 kg sit...
torque rotational equilibrium
2. A 10 kg cat walks along a 3 m long plank with a mass of 4 kg that is supported by two sawhorses. The right sawhorse is 0.7 m from the end of the plank. How far from the end of the right sawhorse can she walk before tipping the plank over. 3. Nintendo has designed a new minigame for the next Sonic Party. In the game, players have to balance a rigid body. Where should...
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