Test each of your claims using a level of significance of .02 Using the p-value method. Show all steps. The test values can be found by the calculator if possible. The p-values must be found using Excel. I am using m = 10 if this not right please change ?below is my data 3 3 3 5 2 3 6 5 6 2 3 5 3 5 2 3 2 3 3 3 4 4 2 3 5 3 3 5 5 2 5 6 5 3 5 5 3 2 3 2 2 2 4 3 3 5 6 2 3 4
step1:
find mean and variance of data
n=50 mean=3.58 Se=0.183
SE=S/sqrt(n)
Step2:
H0: m=4 V/s H1:m noy equal to 4
Step3:
t=2.2951
p-value=0.0260>0.02
reject the null hypothesis.
population mean is not equal to 4 at 0.02 LOS.
excel command =tdist(2.2951,49,2)
Test each of your claims using a level of significance of .02 Using the p-value method....
Use the Minitab display to test the claims using the
significance level of a=0.05. The sample data are the numbers of
support beams manufactured by 4 different operators using 5
different machines. Assume that there is no interaction effect from
operator and machine.
Analysis of Variance for Beams Source DF SS MS F P Operator 3 59.58 20.16 2.5 0.109 Machine 4 93.49 46.22 5.74 0.011 Error 12 47.89 Total 19 200.96 8.05 1. Test the claim that the 4...
(2 points) Use the Minitab display to test the claims using the significance level of a = 0.05. The sample data are the numbers of support beams manufactured by 4 different operators using 4 different machines. Assume that there is no interaction effect from operator and machine. Analysis of Variance for Beams Source DF SS MS F P Operator 3 59.18 20.06 2.59 0.118 Machine 93.51 46.12 5.95 0.016 Error 9 47.75 7.75 Total 15 200.44 3 1. Test the...
p-value Approach: The p-value is the smallest significance level at which the null hypothesis is rejected. While using the normal distribution, suppose, z = Zobserved is the test statistic value for testing the hypothesis about a population mean. This test statistic value is usually negative for a left-tailed test and is usually positive for a right-tailed test. The p-value is obtained with the help of the Standard Normal Distribution Table (Table IV). 1. For a left-tailed test, p-value = P(z<...
4) Given the following information what is the p-value of the test? Using the p-value method would you reject or not reject the null hypothesis at a significance level of 0.05? (8 pts) a) The test statistic for a right-tailed test is z = 0.55 b) The test statistic for a two-tailed test is z = 1.95 c) The test statistic in a left-tailed test is z = -1.72. d) The test statistic for a two-tailed test is z...
Conduct a statistical test at a significance level of 0.05 to determine if there is an association between gender and movie preference. The chart of observed counts has been re-copied here for convenience. Male Female Total Action 52 24 76 Drama 32 32 64 Comedy 20 16 36 Animated 16 8 24 Total 120 80 200 Answer in the blanks to show the work associated with exploring this claim. Blank #1: The statistical test to determine whether there is an...
Use the Minitab display to test
the claims using the significance level of α=0.05. The sample data
are the numbers of support beams manufactured by 5 different
operators using 5 different machines. Assume that there is no
interaction effect from operator and machine. Analysis of Variance
for Beams
SourceOperatorMachineErrorTotalDF441624SS59.3893.0147.81200.2MS20.1646.428.19F2.465.67P0.0870.005
Test the claim that the four operators have the same mean
production output. The F−test statistic is The P-value is Is there
sufficient evidence to warrant the rejection of the claim...
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