(22)
H0:Null Hypothesis: = 60
HA: Alternative Hypothesis: 60
From the given data, the following statistics are calculated:
n = 15
= 940/15 =
62.6667
s = 19.4814
SE =s/
= 62.6667/ =
16.1805
Test statistic is:
t = (62.6667 - 60)/16.1805 = 0.1648
= 0.05
ndf = n - 1 = 15 - 1 = 14
From Table, critical values of t = 2.1448
Since the calculated value of t = 0.1648 is less than critical value of t = 2.1448, the difference is not significant. Fail to reject null hypothesis.
Conclusion:
The data support the claim that these times are from population with a mean equal to 60 seconds.
(14)
H0:Null Hypothesis: 3400
HA: Alternative Hypothesis: < 3400
n = 195
=
3272.8
s = 660.2
SE =s/
= 660.2/ =
47.2779
Test statistic is:
t = (3272.8 - 3400)/47.2779= - 2.6905
= 0.01
ndf = n - 1 = 195 - 1 = 194
From Table, critical values of t = - 2.3457
Since the calculated value of t = - 2.6905 is less than critical value of t = - 2.3457, the difference is significant. Reject null hypothesis.
Conclusion:
The data support the claim that the population of birth weights of males is less than 3600 g..
22. Got a Minute? Students of one of the authors estimated the length of one minute...
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please show work.. also how to get answer on stat crunch
A group of students estimated the length of one minute without reference to a watch or clock, and the times (seconds) are listed below. Use a 0.0 significance level to test the claim that these times are from a population with a mean equal to 60 seconds. Does it appear that students are reasonably good at estimating one minute? 77 93 49 71 51 32 71 72 78 56...