Question

10Cr3+ + 6IO3-+ 22H2O10CrO42- + 3I2+ 44H+

In the above redox reaction, use oxidation numbers to identify the element oxidized, the element reduced, the oxidizing agent and the reducing agent.

name of the element oxidized:

name of the element reduced:

formula of the oxidizing agent:

formula of the reducing agent:

Answer 1

Answer:

=> If the element loses electrons then it is oxidised and if the element gains electrons then it is reduced.

=> The element which is used for reduction of other element is called reducing agent and which is used of oxidation of other element is called oxidising agent.

In the above reaction Cr is oxidised and act as a reducing agent to reduce the Iodine.

And Iodine is reduced? and it is act as oxidising agent to oxidised Cr.

2 4 3 CS +3 43 odala