Question

1. (6 pts) A perion lowers a 0.70 ke bucket at constan a)(0 p) Hew moch work is done by the force of gravity vlrity, Bonus problem: a well to the watee 122 b of gravity while ibd?e 0-78 93, 2S68 J 2. work done by the person lowering the bucket? by the h) (I pt) What was the c)(L pt) The bucket is then filled with water so that ns work done by gravity while it is being palled up? toso 2x cas 180??"::.nt.dq": d) (?ptTwaatsbeworkaaneby the forkin Sx2x Coso 658 s e) (I pt) What is the speed of the bucket when it reaches the top of the wel? ?.62/-$4-6ss-S , .. 1280? -t2in :k"?.kmi C py)tfit takes 8.8 seconds to lift the backet this way, what was the average power aurted y

Answer 1

Work done By Gautity w_g = F^bar . d^bar = mgd cos theta = (0.78) (9.8) (12.2) (B + 0 degree = 93.26 J work Done By PERSON is AGAINST THE BVOY ANT FORCE F_B = P_F V_F q P_F = DENSITY OF DISPLACED FLUID v_F = VOLUME OF DISPLACED FLUID REQUIRED WORK W = (f_d).d^bar By person = (p_f v_f q) d theta = 0 = (997) v_f (9.8)(12.2) w = 119201.32 v_f FOR V_f WE REQUIRED DIMENSION OF RUCKET WILL is NOT GLUEN. On = 5.2 kg work none by gravity w_g = ong.d cos (90 degree) = (5.2) (9.8) (12.2) (- 1) w_g = -298.9 j -uc SHOWS WORK NONE AGAINST GRAVITY w_p = F^bar . d^bar = Fd cos 0 degree = (54) (12.2) = 658.8 j