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The conservative force F- (3.00x 4.00) N does work on a particle moving along the x axis. What is the magnitude of the change in potential energy Gin J) of the particle when the particle moves from x-20 m to a. 10.5 c. 12.5 d. 13.5 e. 14.5

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Answer #1

we know that

work done = change in potential energy

W = \int_{2}^{3}F.dx

W = 1.5x^2 + 4x ( from x = 2 to x = 3)

W = 11.5J

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