The enthalpy of vaporization of mercury is 58.5 kj/mol and the normal boiling point is 630K, You want to calculate the entropy of vaporization for mercury. Which of the following statements concerning this problem is incorrect? Why is this statement incorrect?
A) We wxpect DS to be positive for the vaporization of mercury
B) Once we know that DS is for this process we will know if it is spontaneous
C) We can calculate the entropy of mercury because we know that DG=0 at the normal boiling point
dS = q / T
dS = 58.5 * 10^3 / 630 K
dS = 92.857 J / mol K
option B: Once we know that DS is for this process we will know if it is spontaneous
spontanity of a reaction depends upon gibbs free energy if dG = -ve then it is spontaneous and dG = +ve then the reaction is endothermic.
The enthalpy of vaporization of mercury is 58.5 kj/mol and the normal boiling point is 630K,...
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The standard enthalpy of vaporization (H°vap)
of methylacrylate
(CH2CHCO2CH3) is 36.0
kJ/mol.
The normal boiling point of methylacrylate is
80.5°C.
Calculate the vapour pressure of methylacrylate at
43.0°C.
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