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The progress of a reaction is tracked by following the concentration of one reactant as it is consumed. The table gives the concentration of that reactant at several times. Time (s) 0 10.5 22.3 51.1 69.3 91.6 120.4 160.9 230.3 299.6 [R] (mol/L) 4.00 x 10-3 3.72 x 10-3 3.42 x 10-3 3.12 x 10-3 2.80 x 10-3 2.46 x 10-3 2.11 x 10-3 1.72 x 10-3 1.30 x 10-3 7.98 x 10-4 4.91 x 10-4 a Use graphing software to plot the data as (R) versus time, and determine the average rate for the first 15 s and the average rate from t = 100 to t = 125 s. Enter the rates as positive values. Rate (from t = 0 to t = 15 s) = M's Rate (from t = 100 to t = 125 s) = M/s Submit Previous Next

Answer 1

The plot of [R] vs time can be shown as follows:-

[R] is taken on the y-axis. For convenient we took 10^-3 as common on the graph.

Time is taken on the x-axis.

Se 3.58 3.3 #N-3 in mol/L 2.03 1.89 1.68 1.19 0.49 * 15 100.125. 239.7 299.6 timē in seconds

To calculate the average rate at given time intervals.

We will use the following relation.

Rate of reaction in terms of reactant is given by the decrease in the concentration of the reactant per unit time.

dc Rate =

Where C is concentration of reactant

And t is time.

Minus sign indicate the decrease in concentration of reactant by time.

Rate = =_C2-ci - 72-01

C2 and C1 are the concentration of reactant at time t2 and t1.

Se 3.58 3.3 #N-3 in mol/L 2.03 1.89 1.68 1.19 0.49 * 15 100.125. 239.7 299.6 timē in seconds

to to t=15 t - ta sec sec. concentration C2, 3.58x/3 molle Concentration C2 = 4x10-3 mol/L C₂-C, Rate - tz-t, 23 :-? sortie warok melle] Rate = 0.028x10 mol/lls Thate z 2.8x105 M/s] Imol/L= M1 Auswer. for time /t = loo see to t = 125 sec. I 7,7 100 see cone" C, 22.03 X703 Molle to z 125 sec cone" C = 1.68x10 3 molle - Rate = - {62 - Rebe-f1-58162.032/3* } melle Rate = -2 1.68x10 - 2.03x/ 125-10 S J moll see T Rate = 0.014610-3 mollis I hate z 1.4x105 m/3 l I Auror,