Question

Solve the problem. 18) Assume that women have heights that are normally distributed with a mean of 63.6 inches 18) and a standard deviation of 2.5 inches. Find the value of the quartile Q3. 19) Assume that women's heights are normally distributed with a mean of 63.6 inches and a 19) standard deviation of 2.5 inches. If 90 women are randomly selected, find the probability that they have a mean height between 62.9 inches and 64.0 inches. nste the indicated probability by using the normal distribution as an approximation to the binomial distribution. Estimate 20) A multiple choice test consists of 60 questions. Each question has 4 possible answers of 20) which one is correct.If all answers are random guesses, estimate the probability of getting at least 20% correct.

18-20 Please. Thank you.

Answer 1

18) Given, women's heights are normally distributed with mean Standard deviation σ= 2.5 inches Let value of Qs be k We know that P(X <k) 0.75 H 63.6 inches and X-LL K-63.6 2.5 From standard normal table, at z-0.68, probability value is 0.7517 So, 8. 0.68 K 65.3 Quartile 3=65.3 K-63.6 2.5 19) sample size n-90 x-u 64-63.6 = P(-2.66 s Z s 1.52) -P(Zs 1.52) P(ZS-2.66) 0.9357 0.0039 0.9318