a)
using conservation of momentum
m1 u1 + m2 u2 = m1 v1 + m2 v2
0.253 u1 + 0.373* 0 = 0.253* (- 0.125) + 0.373* 0.645
u1 = 0.826 m/s
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b)
using conservation of energy
dkE = 0.5 m u1^2 - 0.5 ( m1 v1 ^2 +m2 v2^2)
dKE = 0.5* 0.253* 0.826^2 - 0.5* ( 0.253* 0.125^2 + 0.373* 0.645^2)
dKE = 6.743* 10^-3 J
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Comment before rate in case any doubt, will reply for sure.. goodluck
Part A On a frictionless horizontal air table, puck A (with mass 0.253 kg ) is...
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On a frictionless horizontal air table, puck A (with mass 0.249 kg ) is moving toward puck B (with mass 0.369 kg ), which is initially at rest. After the collision, puck A has velocity 0.124 m/s to the left, and puck B has velocity 0.653 m/s to the right. A.What was the speed vAi of puck A before the collision? B.Calculate ΔK, the change in the total kinetic energy of the system that occurs during the collision.
On a frictionless horizontal air table, puck A (with mass 0.249 kg ) is moving toward puck B (with mass 0.367 kg ), which is initially at rest. After the collision, puck A has velocity 0.115 m/s to the left, and puck B has velocity 0.650 m/s to the right. What was the speed vAi of puck A before the collision? Calculate ΔK, the change in the total kinetic energy of the system that occurs during the collision.
On a frictionless horizontal air table, puck A (with mass 0.254 kg ) is moving toward puck B (with mass 0.366 kg ), which is initially at rest. After the collision, puck A has velocity 0.119 m/s to the left, and puck B has velocity 0.650 m/s to the right. 1. What was the speed vAi of puck A before the collision? 2. Calculate ΔK, the change in the total kinetic energy of the system that occurs during the collision.