Two long, parallel wires each carry the same current I = 2.00 A, pointing in opposite direction (see figure below). The two wires are 0.200 m apart. What is the total magnetic field at the point P midway between the wires?
Magnetic field due to long current carrying wire is
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where I is current in wire and r is distance from the wire to
point.
As the current direction in one wire is opposite of other magentic
field due to these wires sums up between them
therefore,
B = oI1/2
r1
+
oI2/2
r2
where r1 r2 are distance from the wires to
point = 0.2m/2 = 0.1m
and
solving we get B = 2xoI/2
(0.1) as current
I is same in both wires
=> B = 8 x 10-6 T
Assume that the wire on the right is wire 1 and that on the left is wire 2.
Also, choose the positive direction for the magnetic field to be out of the page
and negative into the page.
a)At the point halfway between the two points
=Bnet =-B1-B2 =-[ I1/2 pi r1 +
I2/2 pi r2]
=- (4 pi*10^-7 T.m/A)(2) /(2*pi* 0.1) =-4*10^-6 T
Bnet=4 T into the page
This question can be done even without the figure only the
direction cannot be acsertained..Since magnetic field vector is
perpendicular to both current and direction vector, the magnetic
field vector at the required point is perpendicular to the plane of
paper that is it is either coming out of the plane or is directed
inside the plane.Now by using Fleming's Right hand corkscrew
rule,the magnetic at the mid point is added up due to the opposite
direction of current in each wire.Therefore the total magnetic
field at the mid point is:
here the distance applied in formula is half of the distance between the wires
Now putting the values we get magnetic field as 8x10-6Tesla
Answer) At point (a), midway between the wires, the field
from
the top wire is
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