Question

Consider " 2 S2O32-". Which of the following statements is FALSE? 

There are 3 O atoms contained in each unit. 

There are 4 S atoms contained in two units. 

Each unit of S2032 has a ratio of 1 S: 1.5 O 

Two units of S2032 have an overall charge of -4. 

10 atoms are all connected together.

The chemical equation H2 (3)+ O2 (3)>H2O (3) is not balanced. This equation CANNOT be balanced by adding a subscript of 2 behind the oxygen in H20. In other words, you cannot balance the equation this way: H2 (8)+O2 (3) >H202 (3). Why? 

You can only add coefficients when balancing equations so the way to balance the equation would be to show H220 (g) as the product. 

The best way to balance the equation would be to remove the subscript of 2 on the reactant oxygen and show H2 (g) +O(g) >H2O (g). 

You CAN do this. By placing the 2 behind the oxygen in water, you are creating a balanced chemical equation. 

Changing H20 to H2O2 changes the kinds of molecules and completely changes the meaning of a reaction.

Consider the combustion of ethane gas, C2H6. In the balanced chemical equation, what are the lowest, whole number coefficients? Match the number to the species. C2H6+ 02>CO2+H2O 

Answer 1

1) 2 52032 as atom 1 unit = So 0₂ 30 atom (true) 2 Unit = usatom (true) Ratio se 0 (true) 1 1.5 tolle) Chaoge - and 2 Unit have charge = -2 (Talpe) change will be - 2 2 unis = 213=5 atom 2 Unit - 5x2= lo atom 2) 2 H₂ (9) & 02 (9) de 2H₂O (9) 202 is diffesent compound changing Hoo to H₂ Og changes the kind of molecully completely changes the meaning of the reaction ) 3) Ca Hot & 02 - 2002 & 340 2 40 g + 6 Ho or 26H6 & 70 g

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