Chapter 25, Problem 3 In the figure, what is the net electric potential in volts at...

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Answer 1

Answer #1

As we know that electric potential is scalar quantity. so it follows basic scalar addition law.

So, here we have to add all the electric potential at point p due to all four charges.

For +q charges the potential is = kq/d

and for one -q the potential is = -kq/d

and for the far one charge the potential at p is = -kq/2d

now, adding all electric potential at point p

V(net) = kq/d + kq/d -kq/d-kq/2d

V(net) = kq/d(1-1/2)

V(net) = kq/2d

Now as per question, q=6.4 nC or 6.4*10^-9 C and d=3.6cm or 0.036m and k=9×10⁹ N⋅m²⋅C⁻²

V(net) = (9×10⁹ *6.4*10^-9)/2*0.036

V(net) at point P = 800 volts

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Answer 2

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