Question

Thinkabout 10.5 The 2.2 kg block of ice from the is eventually removed from the liquid N2 (after reaching thermal equilibrium with the liquid N2) and placed in a very large amount of liquid H2 at 0°C, where it comes to thermal equilibrium with the liquid H2O. Create a particular model of this process and use it to answer the Big Question: What is the final mass of the ice.

Answer 1

From the given data, we have Amount of Energy by liquid H_2O will be used by ice to increase its temperature from -196 degree c to T_equilibrium. Delta H_ice = delta H_H_2O therefore M_ice CP_i delta T + mice lambda_ice + m_ice CP_w delta T_eq = m_H_2O middot lambda_water + m_H_2O delta T_eq CP_H_2O Amount of Heat Given by H_2O = Amount of Heat gain by ice (delta H_ice) delta H_ice = Latent heat of ice fusion + sencible Heat required to reach t = 0 degree c + sencible4 Heat required to reach t = t_equilibrium delta H_ice = m_ice lambda_ice + m_ice CP_i delta T + m_ice CP_water delta T_eq Amount of heat given by H_2O)delta H_H_2O) delta H_2O = latest heat of Fusion + sensible heat required to reach t = t_equilibrium Given large amount of liquid H_2O at 0 degree c. therefore Equilibrium temp = 0 degree c \r\n therefore m_ice lambda_ice + m_ice CP_i delta T = m_H_2O