here,
F1 = 6.6 N (- i)
F2 = 2.2 N ( j)
let the third force required be F3
as they are in equilibrium
F1 + F2 + F3 = 0
- 6.6 N i + 2.2 N j + F3 = 0
F3 = 6.6 N i - 2.2 N j
the magnitude of force , |F3| = sqrt(6.6^2 + 2.2^2) = 7 N
the direction of force , theta = arctan((-2.2)/6.6) = 162 degree counterclockwise from F1
so the correct option is &)
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