Question

Two charges, Q1= 2.00 ?C, and Q2= 5.60 ?C are located at points (0,-2.50 cm ) and (0,+2.50 cm), as shown in the figure.

What is the magnitude of the electric field at point P, located at (6.50 cm, 0), due to Q₁ alone?

What is the x-component of the total electric field at P?

What is the y-component of the total electric field at P?

What is the magnitude of the total electric field at P?

Now let Q₂ = Q₁ = 2.00 ?C. Note that the problem now has a symmetry that you should exploit in your solution. What is the magnitude of the total electric field at P?

Given the symmetric situation of the previous problem, what is the magnitude of the force on an electron placed at point P?

Answer 1

Given that Two charges a_1 = 2.00 mu c Q_2 = 5.6 mu c located at point (0, -2.5 cm) and (0, plusminus 2.5cm) implies secondary the charge q1 is located on x - axis at point p(6.5 cm, 0) implies concept in this problem In this problem. In electrostatics the intensity of electric field and colum^'s Inverse square. Law is obtained. Implies Formulas are used The electric field E = 1/4 pi epsilon_0 Q/r^2 [1/4 pi epsilon_0 = 9 times 10^9] The force applied In the electric field. F = 1/4 pi epsilon_0 Q_1 Q_2/r^2 implies F = EQ Graph: - Calculations: - firstly we find the electric field at point 'p' on x - axis Q_1 only Placed in point 'P' implies Q_1 = 2.00 mu c = 2 times 10^-6 C implies r = 6.5 cm = 6.5 times 10^-3 cm Now using intensity of electric field at x - axis. E_x = 1/4 pi epsilon_0 a_1/r^2 = 9 times 10^9 times