Question

2) Two fair dice are rolled. Find the following probabilities: (10pts) a) P(the sum of the dice is not eight) b) P(doubles are rolled) c) P(doubles are rolled given that the sum of the dice is eight)

Answer 1

As I wo fair dies are rooted element in sample opace N i Total the sum at the dice dor not eight, let A= sum of dice are eight - Az {(216) (315), (414),(513), (612)}. à no at element in A= 5. - PLA= no. of element in a pored no. insampleoare 36 AO P(B) = - PIA) 36 - Probability of the event sum of dice is not eight = 3 1 = 0.86111

6 A B= doublor are robled, B = 2 c ), (420, (313) (414) (518) (6, 6/8 no. of elementin B = 6 PLB) = 6 = 1 . I & pl doubles are sollikel ) - B = doubles are rolled given that the sum of the dice ireight B= 204140}. no. el element in B = 1 i P(B) = le double dice ane rod led grun that sursum of me freight ) = at 36