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I tried following a few other answers. I got the v= 2.895 m/s I conservation of...

I tried following a few other answers. I got the v= 2.895 m/s

I conservation of energy and tried to account for the changes in height for the box. I'm not sure if this answer is correct.

When a 0.32-kg block is suspended on a vertical spring, it causes it to stretch 2.80 cm. If the block is now pulled 8.50 cm below its equilibrium position and released, what is the speed of the block when it is 4.10 cm below the equilibrium position?

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