L=195.0 cm Delta S= 0.55 cm Thickness of Wire= 0.182 mm the data of the double-slit...

Question

Question

L=195.0 cm

Delta S= 0.55 cm

Thickness of Wire= 0.182 mm

$Single-Slit Diffraction (Fraunhofer Diffraction): (18.2a) W sin(θ)-(n + I/2)a where Wis the slit width, and 0 is the angle be$

science Advanced-Physics

Answer 1

Answer #1

6328メ10-0 X 195 X 102 2. fencebercer difference- 18 D- 18 2 0,23 %

Answer 2

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