Question

bob has just finished climbing a sheet

Bob has just finished climbing a sheer cliff above a level beach and wants to figure out how high he climbed. All he has to use is a baseball, a stopwatch, and a friend on the ground below with a long measuring tape. Bob is a pitcher and knows that the fastest he can throw the ball is about Vo = 35.3 m/s. Bob starts the stopwatch as he throws the ball, with no way to measure the ball's initial trajectory, and watches carefully. The ball rises and then falls, and after t1 = 0.910 s the ball is once again level with Bob. Bob cannot see well enough to time when the ball hits the ground. Bob's friend then measures that the ball hit the ground x = 126 m from the base of the cliff. How high above the beach was the ball when it was thrown?

Answer 1

Concept - use equation of kinematics in vertical and horizontal direction separately to find the required solution as shown below

Take launch pt. as origin at t= tz, Ay=0 AY = (vosino) t, - 1 / 1 g te 3) 0 = 7.30 So, time taken to reach ground is t then x= Volcosolt + t = 3.5985 Now, if ht is h, then ch - (vosinot - £gt? h = 47.4 m

***********************************************************************************************
Check the answer and let me know immediately if you find something wrong or missing... I will rectify the mistakes asap if any