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An open container holds ice of mass 0.540 kg at a temperature of -10.7°C. The mass of the container can be ignored. Heat is s

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Answer: Given, mais m = 0.540 kg, initial temperature T, = -10.4 °C T₂ = 0°c AT= T2-T1 = °C-(-10.7d = 10.78 (01) 10.7k 1 Pow

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