HomeworkLib
Question

Question 4 You mass out 0.554 g of an impure sample of KHP. You use 17.25...

Question 4 You mass out 0.554 g of an impure sample of KHP. You use 17.25 mL of your standardized 0.0994 M NaOH to reach the end point. What percentage of KHP is in your impure sample? The MW of KHP is 204.23 g/mol. The MW of NaOH is 40.00 g/mol.

Group of answer choices

63.2 % KHP

35.018 % KHP

12.4 % KHP

35.0 % KHP

science   chemistry   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Answer #1

-Groen you have assug of Dasm of 0.0994M Nalt import Since KEP and Nadli al mono a 400994M Not under lubanhon- I .14.5 No. 12

0 0
Add a comment
Know the answer?
Add Answer to:
Question 4 You mass out 0.554 g of an impure sample of KHP. You use 17.25...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions

  • A 3.0275 g sample of KHP (a primary standard, 1:1 acid:base, FM=204.23 g/mol) is titrated with...

    A 3.0275 g sample of KHP (a primary standard, 1:1 acid:base, FM=204.23 g/mol) is titrated with 17.25 ml of NaOH using a phenolphthalein end point indicator. What is the concentration of the NaOH solution and the error associated with these measurements?

  • 4. Imagine you perform a complete a titration between an impure KHP sample and NaOH. The...

    4. Imagine you perform a complete a titration between an impure KHP sample and NaOH. The unknown mixture of KHP is weighed and dissolved in approximately 75 ml of distilled water. Three trials are completed, and the following data is collected. Trial 1 Trial 2 Trial 3 Mass of KHP 1.2941 1.2765 1.2985 sample (g) Total volume of 35.28 33.58 36.10 NaOH used (mL) | [NaOH] M) | 0.0972 0.0972 0.0972 a. Calculate the moles of KHP in the sample...

  • This is a challenging question. The titration of an impure sample of KHP found that 36.00...

    This is a challenging question. The titration of an impure sample of KHP found that 36.00 mL of 0.100 M NaOH was required to react completely with 0.758 g of sample. What is the percentage of KHP in this sample? KHP: Potassium Hydrogen Phthalate; It is donating one H+ in an aqueous medium and react with NaOH. Its molecular formula is KHC8H4O4.(Hint: first write the balanced chemical equation for the neutralization of KHP with NaOH). Show your calculation to get...

  • A solution of NaOH needed to be standardized before use in other titrations.   If 0.356 g...

    A solution of NaOH needed to be standardized before use in other titrations.   If 0.356 g of KHP (MW = 204.23 g/mol ) required 30.89 mL of the base to reach the equivalence point, what is the concentration of NaOH? Write a balanced equation to verify titrant: analyte ratio.

  • a sample of impure potassium hydrogen phtalte (KHP,molar mass=204.22g) weighing 2.1283 g required 42.85ml of 0.1084...

    a sample of impure potassium hydrogen phtalte (KHP,molar mass=204.22g) weighing 2.1283 g required 42.85ml of 0.1084 M sodium hydroxide solution for titration to the end point. calulate the percentage of KHP in the sample. [KHP+NaOH->KNaP}+H2O

  • The titration of an impure sample of KHP found that 36.00 mL of 0.100 M NaOH...

    The titration of an impure sample of KHP found that 36.00 mL of 0.100 M NaOH was required to react completely with 0.758 g of sample. What is the percentage of KHP in this sample?

  • Chem 4A 4. Imagine you perform a complete a titration between an impure KHP sample and...

    Chem 4A 4. Imagine you perform a complete a titration between an impure KHP sample and NaOH. The unknown mixture of KHP is weighed and dissolved in approximately 75 ml of distilled water. Three trials are completed, and the following data is collected. Trial 1 Trial 2 Trial 3 Mass of KHP 1.2941 1.2765 1.2985 sample Total volume of 35.28 33.58 36.10 NaOH used (mL NaOHM 0.0972 0.0972 0.0972 a. Calculate the moles of KHP in the sample and the...

  • HELP The titration of an impure sample of KHP found that 36.00 mL of 0.100 M...

    HELP The titration of an impure sample of KHP found that 36.00 mL of 0.100 M NaOH was required to react completely with 0.758 g of sample. What is the percentage of KHP in this sample? KHP: Potassium Hydrogen Phthalate; It is donating one H in an aqueous medium and react with NaOH. Its molecular formula is KHC2H404 (Hint: first write the balanced chemical equation for the neutralization of KHP with NaOH). Show your calculation to get the correct final...

  • Standardization of NaOH solution experiment: A 0.75 g sample of pure acid KHP was titrated to...

    Standardization of NaOH solution experiment: A 0.75 g sample of pure acid KHP was titrated to phenolphthalein endpoint using 45.34 ml NaOH of unknown concentration. The formula weight of pure KHP is 204.22g/mol. Write the chemical equation for the neutralization reaction, indicate the color change of the indicator at the endpoint, and calculate molarity of the NaOH solution. Show your work. 1. Chemical equation ------------- 2. Endpoint color change ---- 3. NaOH molarity --------- Determine percent purity of impure KHP...

  • An unknown sample (0.6855 g) containing KHP is titrated to the equivalence point with 9.7 mL...

    An unknown sample (0.6855 g) containing KHP is titrated to the equivalence point with 9.7 mL of 0.0789 M NaOH. a) How many moles of KHP are present? b) How many grams of KHP are present (molecular weight of KHP = 204.23 g/mol)? c) What is the percent KHP in the sample?

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT