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Problem 3: Calculate the Electrical Field E at the point P(0.0, 4) caused by 4 identical charges of 3 nC each located at P (1
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P(-1,20) 7 P, (1,1,0) 2,00 T 3n0 3nc , 300 Pu (1,1,o) P3 (-1,-1,0) The point Plo,0,40 is on the tz - ani: So to find out theP(0,0,4) P, P = r 4²+(82) - Vis P. : Sa 3nc PIP= P₂P = P₂P = P4 P = V18. Slectric field due to a single charge 15= (kal - 1E

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