Researchers have created every possible "knockout" line in yeast. Each line has exactly one gene deleted and all the other genes present (Steinmetz et al. 2002). The growth rate - how fast the number of cells increases per hour - of each of these yeast lines has also been measured, expressed as a multiple of the growth rate of the wild type that has all the genes present. In other words, a growth rate greater than 1 means that a given knockout line grows faster than the wild type, whereas a growth rate less than 1 means it grows more slowly. Below is the growth rate of a random sample of knockout lines:
0.79, 0.88, 0.61, 0.65, 0.86, 0.68, 0.72, 0.91, 0.97, 0.74, 0.96
What is the variance of growth rate this sample of yeast lines (answer to 6 decimals)?
From the given data
| S.NO. | Sample 1 (X) | X^2 |
| 1 | 0.79 | 0.6241 |
| 2 | 0.88 | 0.7744 |
| 3 | 0.61 | 0.3721 |
| 4 | 0.65 | 0.4225 |
| 5 | 0.86 | 0.7396 |
| 6 | 0.68 | 0.4624 |
| 7 | 0.72 | 0.5184 |
| 8 | 0.91 | 0.8281 |
| 9 | 0.97 | 0.9409 |
| 10 | 0.74 | 0.5476 |
| 11 | 0.96 | 0.9216 |
| Total: | 8.77 | 7.1517 |
![X--,-8.77 0.797273 n 11 anance(s2)-|z?-n-21=1[7.1517-11*0.7972732]=0015962 SD(s)-V0.0 15962 = 0.12634 2-n-2 --Γ7. 15 17-11 * 0.7972732-0015962](http://img.homeworklib.com/questions/8dffd3d0-cabf-11ea-a12b-c3b0439cc357.png?x-oss-process=image/resize,w_560)
Researchers have created every possible "knockout" line in yeast. Each line has exactly one gene deleted...
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