How many calories are required to convert 17g of ice at 0.0 degrees celsius to liquid...
How many calories are required to convert 17g of ice at 0.0 degrees celsius to liquid water at 32.0 degrees celsius. The heat of fusion for water is 80. cal/g
Homework Answers
heat required to melt ice,
Q1 = m*Hfus
= 17 g * 80 cal/g
= 1360 cal
heat required to raise temperature of water from 0oC to
32 oC
Q2 = m*C*(Tf - Ti)
= 17 g * 1 cal / g oC * (32-0) oC
=544 cal
Total heat required = 1360 cal + 544 cal = 1904 cal
Answer: 1904 cal
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