7. For the reaction: N2 + H2 → NH3. What is the mass of the excess...

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Question

7. For the reaction: N2 + H2 → NH3. What is the mass of the excess reagent when 84.06g of N, and 22.18g of Hz are combined? a

science chemistry

Answer 1

Answer #1

no of moles of N2 = W/G.M.Wt

= 84.06/28 = 3 moles

no of moles of H2 = W/G.M.Wt

= 22.18/2.01588 = 11.0026 moles

N2(g) + 3H2(g) -----------------> 2NH3(g)

1 moles of N2 react with 3 moles of H2

3 moles of N2 react with = 3*3/1 = 9 moles of H2

H2 is excess of reagent

The no of moles of excess reagent remains after complete the reaction = 11.0026-9 = 2.002moles of H2

The amount of excess reagent remains after complete the reaction = no of moles * gram molar mass

= 2.002*2.01588

= 4.03g of H2

d. 4.03g >>>>answer

Answer 2

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